(2x+5)(x^2+2x-10)=0

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Solution for (2x+5)(x^2+2x-10)=0 equation: 


Simplifying
(2x + 5)(x2 + 2x + -10) = 0

Reorder the terms:
(5 + 2x)(x2 + 2x + -10) = 0

Reorder the terms:
(5 + 2x)(-10 + 2x + x2) = 0

Multiply (5 + 2x) * (-10 + 2x + x2)
(5(-10 + 2x + x2) + 2x * (-10 + 2x + x2)) = 0
((-10 * 5 + 2x * 5 + x2 * 5) + 2x * (-10 + 2x + x2)) = 0
((-50 + 10x + 5x2) + 2x * (-10 + 2x + x2)) = 0
(-50 + 10x + 5x2 + (-10 * 2x + 2x * 2x + x2 * 2x)) = 0
(-50 + 10x + 5x2 + (-20x + 4x2 + 2x3)) = 0

Reorder the terms:
(-50 + 10x + -20x + 5x2 + 4x2 + 2x3) = 0

Combine like terms: 10x + -20x = -10x
(-50 + -10x + 5x2 + 4x2 + 2x3) = 0

Combine like terms: 5x2 + 4x2 = 9x2
(-50 + -10x + 9x2 + 2x3) = 0

Solving
-50 + -10x + 9x2 + 2x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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